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jAvA 二维数组求和问题

程序二维数组任行求,我帮改完,看看吧.public class thirteen {public static void main(String[] args) {int ab[][]={{1,2,3,4},{1,2,3,4},{1,2,3,4},{1,2,3,4}};for(int i=0;i<ab.length;i++){int sum=0;for(int j=0;j<ab[i].length;j++){sum=sum+ab[i][j];}System.out.

二维数组的话,必须循环行和列,之后求总和即可:public class Test { public static void main(String args[]) throws ParseException { int [][]a = {{1,2,4,5},{6,7,8,9},{10,11,12,13},{14,15,16,17}}; int sum =0; //设置sum为0,方便计算 for(int i = 0; i < a.

public class CountSum { public static void main(String[] args) { double[] 牛奶={357,67,98,345.5,66.5,145.5}; double[] 苹果={135,674,98,345.5,200,245.5}; double[] 肥皂={245,178,98,346,66.5,289}; System.out.println("牛奶: "+getSum(牛奶)

public int sum(int[][] a2){ int sum = 0; for(int i=0;i 评论0 0 0

public class ArraySum{ public static void main(String[] args) { int[] a1 = {1, 2, 3, 4}; int[] a2 = {5, 6, 7, 8}; int sum = 0; for (int i=0; i<a1.length; i++) { sum = sum + a1[i]; } for (int i=0; i<a2.length; i++) { sum = sum + a2[i]; } System.out.println("2数组总和是: " + sum); }}

int类型的求和排序 import java.util.Arrays; public class SortArray { public static void main(String arg[]){ int[] ary = {12, 34, 5, 18, 29, 125, 273, 2}; int sum = 0; for(int i = 0, len = ary.length; i sum += ary[i]; } System.out.println("Sum of array is: " + sum);

使用循环将值遍历进行相加 例:int[] arr={1,2,3,4,5}; int sum=0; for(int a:arr){ sum+=a; }

新定义的数组名字m[i][j]=p就是你放的位置自己选择咯,你求和所有-去最大值和最小值除M-2,就是p,倘若你要放到形参的数组里面,只能扩容一位数组

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